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Question 510279: One number is seven more than twice another. If their sum is decreased by nine, the result is thirteen. Find the numbers.
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "One number is seven more than twice another. If their sum is decreased by nine, the result is thirteen. Find the numbers."
x = one number
2x + 7 = other number {one number is seven more than twice another}
x + 2x + 7 - 9 = 13 {if their sum is decreased by 9, the result is 13}
3x - 2 = 13 {combined like terms}
3x = 15 {added 2 to both sides}
x = 5 {divided both sides by 3}
2x + 7 = 17 {substituted 5, in for x, into 2x + 7}
5 and 17 are the two numbers
For more help from me, visit: www.algebrahouse.com
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