Question 509591: using the equation of a parabola below, find the focus, the directrix, and the equation of the axis of symmetry? x^2=-8y
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! using the equation of a parabola below, find the focus, the directrix, and the equation of the axis of symmetry? x^2=-8y
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Standard form of equation for a parabola: (x-h)^2=4p(y-k), with (h,k) being the coordinates of the vertex.
For given equation: x^2=-8y
This is a parabola that opens downwards with vertex at (0,0)
4p=8
p=2
Focus: (0,-2)
Directrix: y=2
Axis of symmetry: x=0
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