Question 50951This question is from textbook Algebra 2
: y=4x+1 how do I graph this question?
This question is from textbook Algebra 2
Found 2 solutions by checkley71, tutorcecilia:
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! THIS EQUATION IS FOR A LINE WITH A SLOPE OF 4 & A Y INTERCEPT OF 1 [POINT IS
(0,1). NOW SETTING Y=0 AND SOLVING FOR X WE HAVE 0=4X+1 OR 4X=-1 OR X=-1/4 THUS WE HAVE A SECOND POINT (-1/4,0)
NOW PLOT THESES TWO POINTS AND DRAW A LINE BETWEEN THEM & YOU HAVE THE LINE REPRESENTED BY THE EQUATION Y=4X+1.
Answer by tutorcecilia(2152)  (Show Source):
You can put this solution on YOUR website! y=mx+b [The slope-intercept form of a linear equation]
y=any y value
m=the slope of the line
x=any corresponding x value
b = the y-intercept -- where the line crosses the y-axis at point (0, b)
.
y=4x+1
So, the slope (m) = 4 or 4/1 or -4/-1
The y-intercept = (0, 1).
.
To graph, start at the y-intercept (0,1) and follow the slope (4/1). That is, go up 4 spaces and to the right one space.
.
Next, return to the y-intercept (0,1) and follow the other form of the slope (-4/-1). That is, go down 4 spaces and to the left one space.
.
Connect the dots for the graph:
.
|
|
|
