Question 509495: a cash box contained $12.25 in quarters,dimes, and nickles. If there were five more than twice as many dimes as nickles and one less than three times as many quarters as nickles, how many of each coin was there?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! a cash box contained $12.25 in quarters,dimes, and nickles.
If there were five more than twice as many dimes as nickles and one less than three times as many quarters as nickles, how many of each coin was there?
:
"contained $12.25 in quarters,dimes, and nickles."
.05n + .10d + .25q = 12.25
:
"five more than twice as many dimes as nickles"
d = 2n + 5
:
"one less than three times as many quarters as nickles, "
q = 3n - 1
:
In the 1st equation replace d with (2n+5) and replace q with (3n-1)
.05n + .10(2n+5) + .25(3n-1) = 12.25
:
.05n + .20n + .5 + .75n -.25 = 12.25
:
.05n + .20n +.75n + .5 - .25 = 12.25
:
1.00n +.25 = 12.25
:
n = 12.25 - .25
:
n = 12 nickels
:
I'll let you find d and q, check them in the total value equation
|
|
|
