SOLUTION: Given 3 yellow and 4 blue M&M's, how many different ways can they be arranged in a row?

Algebra ->  Probability-and-statistics -> SOLUTION: Given 3 yellow and 4 blue M&M's, how many different ways can they be arranged in a row?      Log On


   



Question 509472: Given 3 yellow and 4 blue M&M's, how many different ways can they be arranged in a row?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given 3 yellow and 4 blue M&M's, how many different ways can they be arranged in a row?
---
Ans: 7!/[3!*4!] = (7*6*5)/(1*2*3) = 35
----------------------------------------
Cheers,
Stan H.
=======