SOLUTION: Josiah has three less than twice as many nickles as dimes. If the total value of hsi coins was $1.45 how many of each kind of coin did he have?
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-> SOLUTION: Josiah has three less than twice as many nickles as dimes. If the total value of hsi coins was $1.45 how many of each kind of coin did he have?
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Question 509404: Josiah has three less than twice as many nickles as dimes. If the total value of hsi coins was $1.45 how many of each kind of coin did he have? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! n = number of nickels
5n = value of nickels in cents
d = number of dimes
10d = value of dimes in cents
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n = 2d -3
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5n + 10d = 145 cents
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substitute
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5(2d-3) + 10d = 145
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10d -15 + 10d = 145
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20d = 160
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d = 8
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n = 2(8) -3
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n = 13
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Check the value to see if this is the correct answer.
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5(13) + 10(8) = 65 + 80 = 145
Correct.
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Answer: Josiah has 8 dimes and 13 nickels.
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Done.
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