SOLUTION: Solve the equation 4x^2 +12x=0
f(x) =4x^2+12x=0 where c is a constant
And part b
Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0
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Quadratic Equations and Parabolas
-> SOLUTION: Solve the equation 4x^2 +12x=0
f(x) =4x^2+12x=0 where c is a constant
And part b
Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0
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Question 509230: Solve the equation 4x^2 +12x=0
f(x) =4x^2+12x=0 where c is a constant
And part b
Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0 Answer by solver91311(24713) (Show Source):
Your question as posed makes very little sense. I think you have left out some things.
If you simply solve , you simply factor out to get giving you roots of 0 and -3.
But your statement: makes no sense at all. Either or .
I suspect that what you are really looking for is: Given
and the fact that the roots of are real and equal, find
Recalling the quadratic formula and the process of evaluating the discriminant, if the discriminant () is equal to zero, then the zeros of the quadratic function are real and equal.
So, noting that
, , and
Solve
for
John
My calculator said it, I believe it, that settles it