Question 509069: Car A leaves at 9am travelling at 40km , Car B leaves the same point at 10am travelling at 60km/h .At what time will car B pass car A? Found 2 solutions by lwsshak3, mananth:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Car A leaves at 9am travelling at 40km , Car B leaves the same point at 10am travelling at 60km/h .At what time will car B pass car A?
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let x=travel time of car B (hrs)
x+1=travel time of car A (hrs)
Distance=travel time*speed (same for both cars)
x(60)=(x+1)(40)
60x=40x+40
20x=40
x=2 hrs
ans:
car B will pass car A at 12 noon
You can put this solution on YOUR website! Car A 40 mph
Car B 60 mph
Car A 10:00
Car B 11:00
Difference in time= 01:00 => 1 hours
Car A will have covered 40 miles before Car B starts
catch up distance= 40 miles
catch up speed = 60 -40 mph
catch up speed = 20 mph
Catchup time = catchup distance/catch up speed
catch up time= 40 / 20
catch up time= 2 hours
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