SOLUTION: If you have a picture that is 4 times as long as it is wide, and a frame that is 2" wide. The combined area of the frame is 252in^2. Find the dimensions of the photo w/o the frame.

Algebra ->  Rectangles -> SOLUTION: If you have a picture that is 4 times as long as it is wide, and a frame that is 2" wide. The combined area of the frame is 252in^2. Find the dimensions of the photo w/o the frame.      Log On


   



Question 509056: If you have a picture that is 4 times as long as it is wide, and a frame that is 2" wide. The combined area of the frame is 252in^2. Find the dimensions of the photo w/o the frame.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
If you have a picture that is 4 times as long as it is wide, and a frame that is 2" wide. The combined area of the frame is 252in^2. Find the dimensions of the photo w/o the frame.
**
let x=length
let y=width
x=4y
..
2*4x+2*4y+4*2^2=252
8x+8y+16=252
8*4y+8y+16=252
32y+8y=252-16
40y=236
y=236/40=5.9 in
x=4y=23.6 in
..
ans:
Dimensions of photo:
length=23.6 in
width=5.9 in