SOLUTION: 2x^3-x^2-6x/2x^2-7x+6

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Question 508970: 2x^3-x^2-6x/2x^2-7x+6
Found 2 solutions by Earlsdon, oberobic:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%5E3-x%5E2-6x%29%2F%282x%5E2-7x%2B6%29 Factor the top and bottom.
2%282x%5E2-x-6%29%2F%282x%5E2-7x%2B6%29=2%282x%2B3%29cross%28%28x-2%29%29%2F%282x-3%29cross%28%28x-2%29%29 Cancel the indicated factors.
2%282x%2B3%29%2F%282x-3%29

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming you problem is:
+%282x%5E3-x%5E2-6x%29%2F%282x%5E2-7x%2B6%29
.
simplify the numerator
.
2x%5E3-x%5E2-6x+=+x%282x%5E2-x-6%29
.
x%282x%5E2-x-6%29+=+x%282x%2B3%29%28x-2%29
.
simplify the denominator
.
+2x%5E2+-7x+%2B6+=+%282x-3%29%28x-2%29+
.
reform the division
.
+%28+x%282x%2B3%29%28x-2%29+%29+%2F+%28+%282x-3%29%28x-2%29+%29+
.
the (x-2) terms will cancel
.
%28x%282x%2B3%29%29+%2F+%28%282x-3%29%29
.
x = 0, x = -3/2