SOLUTION: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148

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Question 508963: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148
Answer by Maths68(1474) About Me  (Show Source):
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Let
1st Interger = x+2
2nd Integer = x+4
3rd Integer = x+6
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Given
5(x+2)+6(x+4)+7(x+6)=148
5x+10+6x+24+7x+42=148
18x+76=148
18x=148-76
18x=72
18x/18=72/18
x=4
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1st Integer = x+2 =4+2=6
2nd Integer = x+4 = 4+4=8
3rd Integer = x+6 = 4+6=10
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Check
(5*6)+6*(8)+7*(10)=148
30+48+70=148
148=148