SOLUTION: The product of the first and third of three consecutive integers is 3 more than 3 times the second integer. Find the integers.

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Question 508540: The product of the first and third of three consecutive integers is 3 more than 3 times the second integer. Find the integers.
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the first, n+1 be the second, n+2 be the third.
Then n*(n+2) = 3 + 3(n+1)
n^2 + 2n = 3 +3n +3
n^2 - n - 6 = 0
(n+2)*(n-3)
n = -2 n =3
I'm assuming we're talking about positive integers, so then our integers are 3, 4,5 <--- Answers