SOLUTION: a tank is filled with 2 pipes. the first pipe can fill the tank in 10 hours. But after it has been opened for3 1/3 hours, the second pipe is opened and the tank is filled up in 4 h
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-> SOLUTION: a tank is filled with 2 pipes. the first pipe can fill the tank in 10 hours. But after it has been opened for3 1/3 hours, the second pipe is opened and the tank is filled up in 4 h
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Question 508410: a tank is filled with 2 pipes. the first pipe can fill the tank in 10 hours. But after it has been opened for3 1/3 hours, the second pipe is opened and the tank is filled up in 4 hours more. how long would it take the second pipe to fill the tank? the two pipes have different diameters. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a tank is filled with 2 pipes. the first pipe can fill the tank in 10 hours.
But after it has been opened for 3 1/3 hours, the second pipe is opened and the tank is filled up in 4 hours more.
how long would it take the second pipe to fill the tank?
the two pipes have different diameters.
:
from the given information we know that the 1st pipe was open for 7 1/3 hrs.
Convert that to hrs
:
let p = the time required by the 2nd pipe to fill the tank
let a full tank = 1
:
A typical mixture equation + = 1
which is + = 1
Multiply by 70p to clear the denominators
22p + 4(70) = 70p
280 = 70p - 22p
280 = 48p
p =
p = 5.83 hrs or 5 hrs 50 minutes
