SOLUTION: A gardener wants to create a rectangular garden with length of 8x - 4y ft. and width of 6x - 6y ft. What is an algebraic expression for the area of the garden? Be sure to multiply
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-> SOLUTION: A gardener wants to create a rectangular garden with length of 8x - 4y ft. and width of 6x - 6y ft. What is an algebraic expression for the area of the garden? Be sure to multiply
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Question 508383: A gardener wants to create a rectangular garden with length of 8x - 4y ft. and width of 6x - 6y ft. What is an algebraic expression for the area of the garden? Be sure to multiply this out, express in simplest correct mathematical form, and include units
someone walk me through this please Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Width = 6x - 6y ft
Length = 8x - 4y ft
Area of rectangle = Width * Length
Area of rectangle =(6x - 6y)(8x - 4y)
Area of rectangle =(6x ) (8x - 4y)- 6y(8x - 4y)
Area of rectangle =48x^2 – 24xy-48xy +24y^2
Area of rectangle =48x^2 +24y^2 –72xy
Area of rectangle =48x^2 –72xy +24y^2 (Square feet)
