SOLUTION: The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Fin
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Question 50827: The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft.
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-16t^2+112t=180
-16t^2+112t-180=0
t= [-112+-sqrt(112^2-4(-16)(-180)]/(-32)
t=0.1645.. seconds
Cheers,
Stan H.
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