SOLUTION: i have absolutley no idea how to solve these problems ! help please ! : 7^7/7 8^2/8^5 2x/2x^3 v/3v^2 2v^3/3uv^3 100a^8 b^12/10a^5 b^15 50x^4 y^3/15x^8 y

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: i have absolutley no idea how to solve these problems ! help please ! : 7^7/7 8^2/8^5 2x/2x^3 v/3v^2 2v^3/3uv^3 100a^8 b^12/10a^5 b^15 50x^4 y^3/15x^8 y       Log On


   

Question 508223: i have absolutley no idea how to solve these problems ! help please ! :
7^7/7
8^2/8^5
2x/2x^3
v/3v^2
2v^3/3uv^3
100a^8 b^12/10a^5 b^15
50x^4 y^3/15x^8 y

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Please limit yourself to one question per question.
What you have shown here could be an entire homework assignment.
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7%5E7+%2F+7+=+7%5E%287-1%29
7%5E%287-1%29=+7%5E6
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Visually, you can see that the denominator 7 cancels one of the 7*7*7*7*7*7*7 in the numerator.
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8%5E2+%2F+8%5E5+=+8%5E%282-5%29
8%5E%282-5%29=+8%5E%28-3%29
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This brings up another fact about exponents:
8%5E%28-3%29+=+1+%2F+8%5E3
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2x%2F2x%5E3=+1%2Fx%5E2
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v%2F3v%5E2+=+1%2F3v
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2v%5E3+%2F+3uv%5E3+=+2%2F3u+
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+%28100a%5E8b%5E%2812%29%29+%2F+%2810a%5E5b%5E%2815%29%29+=+10a%5E3+%2Fb%5E3
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