SOLUTION: how do i set up and solve for problems such as: find three consecutive odd intergers sch that three times the first is 9 greater than six times the third?
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Question 508100: how do i set up and solve for problems such as: find three consecutive odd intergers sch that three times the first is 9 greater than six times the third? Answer by swincher4391(1107) (Show Source):
You can put this solution on YOUR website! Let n be the first
Then n+2 is the second
And n+4 is the third
Then 3n = 9 + 6(n+4)
3n = 9 + 6n + 24
-3n = 33
n = -11
so we have -11, -9, -7 as our three consecutive odd integers.
