SOLUTION: I need to write an equation in slope-intercept form that satisfies each condition; then graph. I am given only that the x-intercept = -4 and the y-intercept = 4. I looked up

Algebra ->  Linear-equations -> SOLUTION: I need to write an equation in slope-intercept form that satisfies each condition; then graph. I am given only that the x-intercept = -4 and the y-intercept = 4. I looked up       Log On


   

Question 50802This question is from textbook Glencoe Agebra 2
: I need to write an equation in slope-intercept form that satisfies each condition; then graph.
I am given only that the x-intercept = -4 and the y-intercept = 4.
I looked up the definitions of x-intercept and y-intercept. And reading in my textbook I see the formula of y = mx+ b. In that formula I understand that m is the slope and b is the y-intercept. But what is the x-intercept in this formula??
Thank you and I hope tonight is possible for an answer? This question is from textbook Glencoe Agebra 2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You are given the x-intercept (x = -4) but that is really the point (-4, 0).
Similarly, the y-intercept (y = 4) is really the point (0, 4).
Now with these two points, you can find the slope, m, using m+=+%28y2-y1%29%2F%28x2-x1%29 where:
(-4, 0) = (x1, y1) and (0, 4) = (x2, y2)
m+=+%284-0%29%2F%280-%28-4%29%29
m+=+4%2F4
m+=+1
Now you can write, in slope-intercept form y+=+mx+%2B+b:
y+=+%281%29x+%2B+b Now substitute the given y-intercept (4) for b.
y+=+x+%2B+4
Now for the graph:
graph%28300%2C200%2C-6%2C5%2C-5%2C6%2Cx%2B4%29
As you can see from the graph, the line intercepts the x-axis (x-intercept) at the point (-4, 0) and it intercepts the y-axis (y-intercept) at the point (0, 4).
The slope (rise over run) can be seen, from the graph, to be 1.