You can put this solution on YOUR website! A man sold 2 acres more than 3/5 of his farm and had 4 acres less than 1/2 of it left. how many acres in the farm.
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change the fractions to .6 and .5
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Let f = no. of acres in his farm
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f - (.6f+2) = .5f - 4
f - .6f - 2 = .5f - 4
f .6f - .5f = -4 + 2
-.1f = -2
f =
f = +20 acres originally in the farm
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See if that check out
20 - .6(20) - 2 = .5(20) - 4
20 - 12 - 2 = 10 - 4
6 = 6; confirms our solution of f = 20