SOLUTION: Solve the system of equations. 2x-y+z=3 x+3y-2z=11 3x-2y+4z=1

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Question 507501: Solve the system of equations.
2x-y+z=3
x+3y-2z=11
3x-2y+4z=1
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the given system of equations

system%282x-y%2Bz=3%2Cx%2B3y-2z=11%2C3x-2y%2B4z=1%29


Convert to matrix form

%28matrix%283%2C4%2C2%2C-1%2C1%2C3%2C1%2C3%2C-2%2C11%2C3%2C-2%2C4%2C1%29%29


Now row reduce to rref form
(Solution provided by the Linear Algebra Toolkit)



(Solution provided by the Linear Algebra Toolkit)


The values in the right most column are 3, 2, and -1.


So the solutions are x=3, y=2 and z=-1


Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim