You can put this solution on YOUR website! a baseball is hit so that its height in feet after t seconds is s(t)=-16tsquared +44t+4 find the maximum height of the baseball
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s(t)=-16tsquared +44t+4
s(t)=-16t^2 +44t+4
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Because the coefficient associated with the t^2 term is negative, we know it is a parabola that opens downwards.
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therefore, the vertex is the max.
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height is max when:
t = -b/(2a)
t = -44/(2(-16))
t = -44/(-32)
t = 1.375 secs
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max height:
s(t)=-16t^2 +44t+4
s(1.375)=-16(1.375)^2 +44(1.375)+4
s(1.375)=-16(1.890625) +60.5+4
s(1.375)=-30.25 +60.5+4
s(1.375)= 34.25 feet
