Question 507300: The sum of the ages of a woman and her son is 36 years. Six years from now the woman will be twice as old as her son. How old is each now? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The sum of the ages of a woman and her son is 36 years. Six years from now the woman will be twice as old as her son. How old is each now?
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Equations:
w + s = 36
(w+6) = 2(s+6)
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Substitute for "w" and solve for "s":
36-s+6 = 2s+12
3s = 30
s = 10 yrs old (son's age now)
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Solve for "w":
w + s = 36
w + 10 = 36
w = 26 (mother's age now)
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Cheers,
Stan H.
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