SOLUTION: how do i put 4(x-4)squared + 4ysquared = 16 into standard form. I need to be able to find the center of a circle and the radius

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Question 507257: how do i put 4(x-4)squared + 4ysquared = 16 into standard form.
I need to be able to find the center of a circle and the radius
Found 2 solutions by Gogonati, lwsshak3:
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
Divide both sides of 4%28x-4%29%5E2%2B4y%5E2=16 by 4 and get the standard form:
%28x-4%29%5E2%2B%28y%2B0%29%5E2=2%5E2, that represent a circle centered at (4, 0) and radius 2

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how do i put 4(x-4)squared + 4ysquared = 16 into standard form.
I need to be able to find the center of a circle and the radius
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4(x-4)^2+4y^2=16
Divide by 4
(x-4)^2+y^2=4
This is an equation of a circle of the standard form: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates of the center and r=radius
For given equation:
Center: (4,0)
Radius: √4=2