SOLUTION: Express the given quantity as a single logarithm. 1/9 ln(x + 2)^9 + 1/2[ln x − ln(x2 + 3x + 2)^2]

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Question 507252: Express the given quantity as a single logarithm.

1/9 ln(x + 2)^9 + 1/2[ln x − ln(x2 + 3x + 2)^2]

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Express the given quantity as a single logarithm.
1/9 ln(x + 2)^9 + 1/2[ln x − ln(x2 + 3x + 2)^2]
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= ln[(x+2)^9]^(1/9) + ln(x^1/2) - ln(x^2+3x+2)
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= ln(x+2) + ln(x^(1/2)) - ln(x^2+3x+2)
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= ln[(x^(1/2)*(x+2)/(x^2+3x+2)]
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= ln[x^(1/2)/(x+1)]
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Cheers,
Stan H.