SOLUTION: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle.

Algebra ->  Rectangles -> SOLUTION: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle.      Log On


   

Question 506870: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle.
Answer by emargo19(101) About Me  (Show Source):
You can put this solution on YOUR website!
Let w be the width
length= w+2
Area=w(w+2)
Perimeter=2(w)+2(w+2)-8
%28w%2B2%29w=2%28w%29%2B2%28w%2B2%29-8
w%5E2%2B2w=2w%2B2w%2B4-8
w%5E2%2B2w=4w-4
w%5E2-2w%2B4=0
Next solve using Quadratic Formula.