SOLUTION: How do you solve this word problem: Roger, Sue and Tim have $90 between them. Roger has halt the amount that Sue has. If Sue gives Tim $5, he will have twice as much as she doe

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: How do you solve this word problem: Roger, Sue and Tim have $90 between them. Roger has halt the amount that Sue has. If Sue gives Tim $5, he will have twice as much as she doe      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 50618: How do you solve this word problem:
Roger, Sue and Tim have $90 between them. Roger has halt the amount that Sue has. If Sue gives Tim $5, he will have twice as much as she does. How much does each one have?
Please show and explain each step. Thank you so much.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Roger, Sue and Tim have $90 between them. Roger has half the amount that Sue has. If Sue gives Tim $5, he will have twice as much as she does. How much does each one have?
-----------------
Assume Roger has "x".
Then Sue has "2x".
And Tim will have 2(2x-5)= 4x-10
EQUATION:
x+2x+4x-10 = 90
7x=100
x=$14.29 {amount Roger has)
2x=$28.57 (amount Sue has)
4x-10= $47.28 (amount Tim has)

These numbers don't add up to exactly $90 because of
rounding off.
Cheers,
Stan H.