SOLUTION: Find the vertex of each parabola. 18. x^2 + 4x - 28y + 88 = 0 19. x^2 - 2x + 44y + 353 = 0 20. x^2 + 6x + 8y + 25 = 0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex of each parabola. 18. x^2 + 4x - 28y + 88 = 0 19. x^2 - 2x + 44y + 353 = 0 20. x^2 + 6x + 8y + 25 = 0       Log On


   



Question 50606: Find the vertex of each parabola.
18. x^2 + 4x - 28y + 88 = 0
19. x^2 - 2x + 44y + 353 = 0
20. x^2 + 6x + 8y + 25 = 0

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
18. x^2 + 4x - 28y + 88 = 0
Rewrite as follows:
x^2+4x+? = 28y-88+?
Complete the square to get:
x^2+4x+4 = 28y-88+4
(x+2)^2 = 4(7)(y-(11/7))
This follows the form (x-h)^2=4p(y-k)
where (h,k) is the vertex.
Vertex at (-2,11/7)
Follow the same procedure for #'s 19 and 20.
19. x^2 - 2x + 44y + 353 = 0
20. x^2 + 6x + 8y + 25 = 0
Cheers,
Stan H.