SOLUTION: find two consecutive even integers such that three times the first equals twice the second

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Question 505969: find two consecutive even integers such that three times the first equals twice the second
Answer by Maths68(1474) About Me  (Show Source):
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Let
1st Interger = x+2
2nd Interger = x+4
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Given
3(x+2)=2(x+4)
3x+6=2x+8
3x-2x=8-6
x=2
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1st Interger = x+2 = 2+2=4
2nd Interger = x+4 = 2+4=6
===========================================
Check
3*4=2*6
12=12