SOLUTION: factor: 4y^3+12y^2-y-3 Im confused because its a quadratic...

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Question 505745: factor:
4y^3+12y^2-y-3
Im confused because its a quadratic...
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

4y%5E3%2B12y%5E2-y-3 Start with the given expression


%284y%5E3%2B12y%5E2%29%2B%28-y-3%29 Group the terms in two pairs


4y%5E2%28y%2B3%29-1%28y%2B3%29 Factor out the GCF 4y%5E2 out of the first group. Factor out the GCF -1 out of the second group


%284y%5E2-1%29%28y%2B3%29 Since we have the common term y%2B3, we can combine like terms


%282y-1%29%282y%2B1%29%28y%2B3%29 Now factor 4y%5E2-1 to get %282y-1%29%282y%2B1%29 (use the difference of squares formula)


So 4y%5E3%2B12y%5E2-y-3 factors to %282y-1%29%282y%2B1%29%28y%2B3%29


In other words, 4y%5E3%2B12y%5E2-y-3=%282y-1%29%282y%2B1%29%28y%2B3%29

Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim