SOLUTION: Please solve: x^4 - 4x^3 + 3x / x^2 -1 I get x^2 - 4x + 1 - x + 2/x^2 - 1

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Question 5057: Please solve:
x^4 - 4x^3 + 3x / x^2 -1
I get x^2 - 4x + 1 - x + 2/x^2 - 1

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
+%28x%5E4+-+4x%5E3+%2B+3x%29+%2F+%28x%5E2+-+1%29

First factor out the x from the numerator, and factor the denominator:
+%28x%28x%5E3+-+4x%5E2+%2B+3%29+%29%2F+%28%28x+-+1%29%28x%2B+1%29+%29++

Now the trick is this: Is +x%5E3+-+4x%5E2+%2B+3+ divisible by either (x-1) or (x+1). It turns out (and it usually does!) that it is, in this case, divisible by (x-1). You will have to do synthetic or polynomial division (which I don't know how to do on this website!) as follows:
Divide:
1 | 1 -4 0 3
XXX 1 -3 -3
_____________________
XX 1 -3 -3 0

Other tutors could probably write it better, but basically, the remainder is zero, and the quotient is x%5E2+-+3x+-+3

Therefore the x-1 divides out leaving this:
+%28x%28x-1%29+%28x%5E2+-+3x+-+3%29+%29%2F+%28%28x+-+1%29%28x%2B+1%29+%29++
+%28x+%28x%5E2+-+3x+-+3%29+%29%2F+%28x%2B+1%29+

By the way, the remaining trinomial does not factor.

R^2 at SCC