SOLUTION: A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square cent
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Question 505296: A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimentions of the original rectangle? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimentions of the original rectangle?
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original rectangle:
let x=width
4x=length
area=x*4x=4x^2
..
2nd rectangle
x+2=width
4x+3=length
area=(x+2)(4x+3)=4x^2+11x+6
..
original area+530=2nd area
4x^2+530=4x^2+11x+6
11x+6=530
11x=530-6=524
x=524/11=47.64 cm
4x=190.55 cm
ans:
dimensions of original rectangle:
width=47.64 cm
length=190.55 cm
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