SOLUTION: what value of x satisfies the given conditions: y1=10(2x-1),y2=2x+1, and y1 is 14 more than 8 times y2.

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Question 504657: what value of x satisfies the given conditions: y1=10(2x-1),y2=2x+1, and y1 is 14 more than 8 times y2.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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what value of x satisfies the given conditions: y1=10(2x-1),y2=2x+1, and y1 is 14 more than 8 times y2.
:
Three equations
y1 = 10(2x-1)
y1 = 20x - 10
and
y2 = 2x + 1
and
y1 = 8(y2) + 14
Find y1 in terms of x, replace y2 with (2x+1)
y1 = 8(2x+1) + 14
y1 = 16x + 8 + 14
y1 = 16x + 22
:
Back to the 1st equation, replace y1 with (16x+22)
16x + 22 = 20x - 10
22 + 10 = 20x - 16x
32 = 4x
x = 32%2F4
x = 8 satisfies the equations
:
:
:
Confirm this solution, find y2
y2 = 2x + 1
y2 = 2(8) + 1
y2 = 17
and y1
y1 = 20x -10
y1 = 20(8) - 10
y1 = 150
:
Check for equality in the equation: y1 = 8(y2) + 14
150 = 8(17) + 14
150 = 136 + 14; confirms our solution of x=8