SOLUTION: At a certain high school, the respective weights for the following subjects are Mathematics 3, English 3, History 2, Science 2 and Art 1. What is a student’s average whose ma

Algebra ->  Human-and-algebraic-language -> SOLUTION: At a certain high school, the respective weights for the following subjects are Mathematics 3, English 3, History 2, Science 2 and Art 1. What is a student’s average whose ma      Log On


   



Question 5044: At a certain high school, the respective weights for the following subjects are Mathematics 3, English 3, History 2, Science 2 and Art 1. What is a student’s average whose marks were the following: Geometry 89, American Literature 92, American History 94, Biology 81, and Sculpture 85?
Answer by arunpaul(104) About Me  (Show Source):
You can put this solution on YOUR website!
weight for math = 3=w1
weight for english = 3=w2
that for history = 2=w3
that for science = 2 =w4
that for arts = 1=w5
total of weight = w = w1 +w2 + w3+ w4 +w5 = 3+3+2+2+1=11
geometry mark = 89
American literature = 92
American history = 94
Biology = 81
sculpture = 85
so average = ((89*w1)+(92*W2)+(94*W3)+(81*w4)+(85*w5)/(w1+w2+w3+w4+w5)
=((89*3)+(92*3)+(94*2)+(81*2)+(85*1)/(w1+w2+w3+w4+w5)
=978/11=88.909
(Ans) (mail me to my address arun_662002@yahoo.co.in)
so average =