SOLUTION: Angle A is twice as large as its complement <B

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Question 50435: Angle A is twice as large as its complement
Answer by tutorcecilia(2152) About Me  (Show Source):
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Angle A is twice as large as its complement AngleA + AngleB = 90 [Definition of complimentary angles]
AngleA = 2(AngleB)
AngleB=AngleB
.
2(AngleB) + AngleB = 90 [Plug-in the values]
3 AngleB=90 [Solve for AngleB]
3/3 AngleB=90/3
AngleB=30
.
AngleA=(2)(30) = 60
.
Checking:
60+30=90
90=90 [Checks out]