SOLUTION: find the slope of the line that contains the points:P1 (-4,10) and P2 (6,-10)?
i got the answer
-10-10 over -6-4= 0 over 10 =0
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-> SOLUTION: find the slope of the line that contains the points:P1 (-4,10) and P2 (6,-10)?
i got the answer
-10-10 over -6-4= 0 over 10 =0
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You can put this solution on YOUR website! P1 = (-4,10)
P2 = (6,-10)
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slope = change in y / change in x
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change in y = -10 -10 = -20
change in x = 6 -(-4) = 10
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slope = -20/10 = -2
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y = -2x + b
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We can substitute one of the known points to find 'b'.
Use P1, (-4,10)
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10 = -2(-4) + b
10 = 8 + b
b = 2
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y = -2x +2
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We can check this solution using the other point, P2 = (6,-10).
y = -2x + 2
y = -2(6) + 2
y = -12+2
y =10
OK
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