Question 503881: Write an equation of a circle with endpoints of the diameter at (-3, -7) and (14, 22)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Write an equation of a circle with endpoints of the diameter at (-3, -7) and (14, 22)
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Standard form of equation for circle: (x-h)^2+(y-k)^2=r^2, with (h,k) being the (x,y) coordinates or the center, r=radius
Using midpoint formula to find center of circle:
(x1+x2)/2, (y1+y2)/2
=(14-3)/2, (22-7)/2
=11/2,15/2
center(11/2,15/2)
Use distance formula to find radius of circle (between center and one of given endpoint (-3,-7)
r^2=(x1-x2)^2+(y1-y2)^2
=(-3-11/2)^2+(-7-15/2)^2
=72.25+210.25
=282.5
Equation of circle:
(x-11/2)^2+(y-15/2)^2=282.5
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