SOLUTION: You have a wire that is 53 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The other piece will be bent into the shape of a circle.

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: You have a wire that is 53 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The other piece will be bent into the shape of a circle.       Log On

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Question 503532: You have a wire that is 53 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The other piece will be bent into the shape of a circle. Let A represent the total area of the square and the circle. What is the circumference of the circle when A is a minium?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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You have a wire that is 53 cm long. You wish to cut it into two pieces.
One piece will be bent into the shape of a square. The other piece will be bent into the shape of a circle.
Let A represent the total area of the square and the circle.
What is the circumference of the circle when A is a minimum?
:
Let x = circumference of the circle
then
(53-x) = the perimeter of the square
and
%2853-x%29%2F4 = the side of the square
and
%28%2853-x%29%2F4%29%5E2 = the area of the square
:
Find the area of the circle using the circumference
find the radius (r)
2*pi*r = x
r = x%2F%282%2Api%29
r = x%2F6.28
Find the area of the circle
A = pi%2Ar%5E2
Replace r with x%2F6.28
A = pi*%28x%2F6.28%29%5E2 = pi*%28x%5E2%2F39.48%29
cancel pi into 39.48
A = x%5E2%2F12.566
Total area of circle and square
A = x%5E2%2F12.566 + %28%2853-x%29%2F4%29%5E2 = x%5E2%2F12.566 + %28%282809-106x%2Bx%5E2%29%2F16%29
:
convert these fractions to decimal coefficients
A(x) = .0796x^2 + .0625x^2 - 6.625x + 175.5625
A(x) = .1421x^2 - 6.625x + 175.5625
:
Find the axis of symmetry of this quadratic equation (min area)
x = %28-%28-6.625%29%29%2F%282%2A.1421%29
x = 6.625%2F.2842
x = 23.31 cm is the circumference when they have min area