SOLUTION: someone please help and show me the steps:thank you so very much Joe has $39.17 in pennies and nickels. If he has 1585 coins in all, how many of each type does he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: someone please help and show me the steps:thank you so very much Joe has $39.17 in pennies and nickels. If he has 1585 coins in all, how many of each type does he have?      Log On

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Question 503259: someone please help and show me the steps:thank you so very much
Joe has $39.17 in pennies and nickels. If he has 1585 coins in all, how many of each type does he have?

Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
pennies x numbers
nickels y numbers

1 x + 1 y = 1585 .............1
1 x + 5 y = 39.17 .............2
Eliminate y
multiply (1)by -5
Multiply (2) by 1
-5 x -5 y = -7925
1 x 5 y = 3917
Add the two equations
-4 x = -4008
/ -4
x = 1002.00 OR 1002
plug value of x in (1)
1 x + 1 y = 1585
1002 + 1 y = 1585
1 y = 1585 -1002
1 y = 583
y = 583
pennies 1002 numbers
nickels 583 numbers

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let p = number of pennies he has
Let n = number of nickels he has
given:
(1) +p+%2B+n+=+1585+
(2) +1%2Ap+%2B+5n+=+3917+ ( in cents )
Subtract (1) from (2)
(2) +p+%2B+5n+=+3917+
(1) +-p+-+n+=+-1585+
+4n+=+2332+
+n+=+583+
and, since
(1) +p+%2B+n+=+1585+
(1) +p+%2B+583+=+1585+
(1) +p+=+1585+-+583+
(1) +p+=+1002+
He has 1002 pennies and 583 nickels
check answer:
(2) +p+%2B+5n+=+3917+
(2) +1002+%2B+5%2A583+=+3917+
(2) +1002+%2B+2915+=+3917+
(2) +3917+=+3917+
OK