SOLUTION: Please help me with this: {{{ sqrt(5t+4)-2sqrt(t)=1 }}} I squared both sdes and then I moved one part over to the other side. Please help.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me with this: {{{ sqrt(5t+4)-2sqrt(t)=1 }}} I squared both sdes and then I moved one part over to the other side. Please help.      Log On


   

Question 503039: Please help me with this: +sqrt%285t%2B4%29-2sqrt%28t%29=1+ I squared both sdes and then I moved one part over to the other side. Please help.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%285t%2B4%29-2sqrt%28t%29=1+
+sqrt%285t%2B4%29=2sqrt%28t%29%2B1+
Square both sides
5t%2B4+=+%282sqrt%28t%29%2B1%29%5E2
5t%2B4=4t%2B2sqrt%28t%29%2B1
5t%2B4-1-4t=2sqrt%28t%29
t%2B3=2sqrt%28t%29
square
%28t%2B3%29%5E2=4t
t%5E2%2B6t%2B9=4t
t%5E2%2B2t%2B9=0
Find the roots of the equation by quadratic formula

a= 1 ,b= 2 ,c= 9

b^2-4ac= 4 + -36
b^2-4ac= -32
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x=%28-2%2B-+sqrt%28+4-36%29%29%2F2