SOLUTION: x= 12 y=8 z=3 (x/y)2 -3y-z/(x-y)2 =
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Question 50303
This question is from textbook
Algebra 1
:
x= 12 y=8 z=3
(x/y)2 -3y-z/(x-y)2 =
This question is from textbook
Algebra 1
Answer by
seawind(8)
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use substitution
(12/8)2-3*8-3/(12-8)*2
=3-24-3/4*2
=3-24-3/2
=-21-3/2
=-42/2-3/2
=-45/2