SOLUTION: Hello: This one has me stumped. The probability that Student A comes to class is .99. INDEPENDENTLY, the probability that Student B comes to class is .98. The probability that

Algebra ->  Probability-and-statistics -> SOLUTION: Hello: This one has me stumped. The probability that Student A comes to class is .99. INDEPENDENTLY, the probability that Student B comes to class is .98. The probability that       Log On


   

Question 502900: Hello:
This one has me stumped. The probability that Student A comes to class is .99. INDEPENDENTLY, the probability that Student B comes to class is .98. The probability that NEITHER attend class is (this is what the answer is I must come up with)? Is this where an intersection would come in? P(A intersect B) Thank you for any assistance you can provide. :)

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Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

Both are independent events.
probability that Student A doesn't attend the class = 1- 0.99 = 0.01
probability that Student B doesn't attend the class = 1- 0.98 = 0.02

probability that neither attend class = 0.01 *0.02 = 2/10000 = 0.0002