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Question 502894: slope 8/9, passing through (3,-1)
Answer by Maths68(1474)   (Show Source):
You can put this solution on YOUR website! slope m = 8/9
Point (x, y)=(3, -1)
Equation of Slope-Intercept Form
y=mx+b .........(1)
Plug in the values in above equation
-1=8/9*(3)+b
-1=8/3+b
-3=8+3b
-3-8=3b
-11=3b
-11/3=b
Plug in the value of b and m in (1)
y=8/9(x)-11/3
y=(8x/9)-(11/3)
Taking LCM on right hand side
y=[8x-(11*3)]/9
y=[8x-33]/9
y=8x/9-33/9
y=(8/9)x-11/3
Equation of the line is
y=(8/9)x-11/3
Second Method
Equation of line Point-Slope Form
m=(y1-y)/(x1-x)
Given
slope m = 8/9
Point (x1, y1)=(3, -1)
Plug in the values
8/9=(-1-y)/(3-x)
8/9(3-x)=(-1-y)
Multiply by 9 both sides of the above equation
8(3-x)=9*(-1-y)
24-8x=-9-9y
24=-9-9y+8x
24+9=-9y+8x
33=-9y+8x
9y=8x-33
Divide by 9 both side of the equation
9y/9=(8x-33)/9
y=8x/9 - 33/9
Equation of the line is
y=8/9(x) - 11/3
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