Question 502711: -5m+2+8m=2m+11
Answer by persian52(161)   (Show Source):
You can put this solution on YOUR website! -5m+2+8m=2m+11
According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, m is a factor of both -5m and 8m.
(-5+8)m+2=2m+11
To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of -5 and 8 and give the result the same sign as the integer with the greater absolute value.
(3)m+2=2m+11
Remove the parentheses.
3m+2=2m+11
Since 2m contains the variable to solve for, move it to the left-hand side of the equation by subtracting 2m from both sides.
3m+2-2m=11
According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, m is a factor of both 3m and -2m.
(3-2)m+2=11
To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 3 and -2 and give the result the same sign as the integer with the greater absolute value.
(1)m+2=11
Remove the parentheses.
m+2=11
Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides.
m=-2+11
Add 11 to -2 to get 9.
m=9
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