SOLUTION: five years ago chloe was twice as old as danny. seven years hence, three times chloe's age will be four times danny's age .ow old each now?
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Question 502348: five years ago chloe was twice as old as danny. seven years hence, three times chloe's age will be four times danny's age .ow old each now? Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Let
Present age of Chloe = c
Present age of Danny = d
Given
Five years ago means we have to subtract 5 from their present age
c-5=d-5
then
Chloe was twice as old as Danny
(c-5)=2(d-5)
c-5=2d-10
c=2d-10+5
c=2d-5...............(1)
Seven years hence means we have to add 6 in their present age
c+7=d+7
then
Three times Chloe's age will be four times Danny's age
3(c+7)=4(d+7)
3c+21=4d+28
3c=4d+28-21
3c=4d+7..............(2)
Put the value of c from (1) to (2)
3c=4d+7
3(2d-5)=4d+7
6d-15=4d+7
6d=4d+7+15
6d-4d=22
2d=22
divide by 2 both sides of the above equation
2d/2=22/2
d=11
Put the value of d in (1)
c=2d-5...............(1)
c=2(11)-5
c=22-5
c=17
Present age of Chloe = c = 17 years
Present age of Danny = d = 11 years
