SOLUTION: Joe and Gayne lives 3 miles apart. They both leave their houses at the same time and walk to meet each other. Joe walks at 2.5mi/h and Gayne walks at 3.5mi/h. How far will be Joe w
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Question 502307: Joe and Gayne lives 3 miles apart. They both leave their houses at the same time and walk to meet each other. Joe walks at 2.5mi/h and Gayne walks at 3.5mi/h. How far will be Joe walk before he meets Gayna? Answer by geetha_rama(94) (Show Source):
You can put this solution on YOUR website! Let at time t joe and gayna meet
Distance covered by joe in time t is
d = 2.5*t -> eauaion 1
Distance covered by Gayna in time t
3-d = 3.5*t
from equation 1,
=>3 - 2.5t = 3.5t
3 = 6t
t = 1/2 hr
Distance travelled by joe in 1/2 hr is 2.5*1/2 = 1.25 miles
Jpe would haved walked 1.25 miles before meeting Gayna
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