You can put this solution on YOUR website! Find the exact value of sec[sin^-1(-3/4)]
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sin^-1(-3/4)=sin inverse
Given problem asks to find the sec of an angle whose sine is (-3/4) in quadrant IV
The cos of this same angle is then=4/5 (working with a 3-4-5 right triangle in quad IV)
sec[sin^-1(-3/4)]=1/cos=5/4
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