SOLUTION: log4x+log4(x+12)=3 (x)(x+12)=4^3 x^2+4x+12=48 x^2+4x=36 x(x+12)=36 x=? I'm missing something right?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log4x+log4(x+12)=3 (x)(x+12)=4^3 x^2+4x+12=48 x^2+4x=36 x(x+12)=36 x=? I'm missing something right?      Log On


   

Question 50122: log4x+log4(x+12)=3
(x)(x+12)=4^3
x^2+4x+12=48
x^2+4x=36
x(x+12)=36
x=?
I'm missing something right?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log4x+log4(x+12)=3
(x)(x+12)=4^3
x^2+12x-64=0
(x+16)(x-4)=0
x=4
Cheers,
Stan H.