Question 500992: When the sum of 8 and twice a positive number is subtracted from the square of the number, 0 results. find the number Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! When the sum of 8 and twice a positive number is subtracted from the square of the number, 0 results. find the number
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Given: sum of 8 and twice a positive number [x] -> 8 + 2x
Given: subtracted from the square of a number -> x^2 - (8 + 2x)
Given: result is 0 -> x^2 - (8 + 2x) = 0
x^2 - 2x - 8 = 0
This can be factored as:
(x-4)(x+2) = 0
Take the positive solution:
x = 4
