SOLUTION: the sum of three times one number and seven times another is 62. the difference between the numbers is 4. what are the numbers?

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Question 500750: the sum of three times one number and seven times another is 62. the difference between the numbers is 4. what are the numbers?
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
x = one number
y = another number
.
3x + 7y = 62
.
the difference between x & y = 4
x - y = 4
x = y +4
.
substitute for x
.
3(y+4) +7y = 62
.
3y +12 +7y = 62
10y = 50
y = 5
.
substitute y = 5 to find x
.
x = y+4
x = 5+4
x = 9
.
Always check your answer.
.
3(9) + 7(5) = ?
27 + 35 = 62
Correct.
.
Answer: The two numbers are 5 and 9.
.
Done.