SOLUTION: A gardener has 26 lb of a mixture of fertilizer and weed killer. If 1 lb of the mixture is replaced by weed killer the result is a mixture that is 5 percent weed killer. What perce
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Question 500263: A gardener has 26 lb of a mixture of fertilizer and weed killer. If 1 lb of the mixture is replaced by weed killer the result is a mixture that is 5 percent weed killer. What percent of the original mixture was weed killer? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A gardener has 26 lb of a mixture of fertilizer and weed killer.
If 1 lb of the mixture is replaced by weed killer the result is a mixture that is 5 percent weed killer.
What percent of the original mixture was weed killer?
:
Let x = decimal equiv of the original mixture's weed killer percent
:
That would leave 25 lb of the original mixture used in this mixture
:
Mixture + weed killer = 5% mixture
25x + 1 = .05(25 + 1)
25x + 1 = 1.25 + .05
25x = 1.3 - 1
25x = .3
x =
x = .012 * 100 = 1.2% weed killer originally
